The digits 5, 6, 7, 8, and 9 are randomly arranged to form a three-digit number. (Digits are not repeated) Find the probability that the number is even and greater than 900 The probability that the three-digit number is even and greater than 900 is (Type an integer or a simplified fraction.)

Answer:The probability that the three digit number is even and greater than 900 is 0.1Step-by-step explanation:Since digits are not repeated, we have 5 options for the first digit, then 4 options for the second one and 3 options for the third one. The amount of possible 3 digit numbers is: 5 x 4 x 3 = 60.a) If the number is even and greater than 900, then the first digit has to be 9 (so we have only one option), the third digit can be either 6 or 8 (2 options) and the second digit can be either of the three remaining digits. Therefore the amount of digits possible is: 1 x 3 x 2 = 6.The probability of the number being even and greater than 900 is 6/60= 0.1